Raashid Shah

Q.1 Salil wants to put a picture in a frame. The picture is 7 3/5 cm wide. To fit in the frame the picture cannot be more than 7 3/10 cm wide. How much should the picture be trimmed ? A) 3/9 B) 2/10 C) 3/10 D) 2/9 Ans. C Therefore, picture to be trimmed Thus picture should be trimmed by 3/10 cm Q.2 Suman studies for 5 2/3 hours daily. She devotes 4 2/5 hours of her time for Science and Mathematics. How much time does she devote for other subjects? A) 1 13/15 B) 2 13/15 C) 1 12/15 D) 2 12/15 Ans. B Total time of Suman’s study =5 2/3 hr = 17/3 hr.Time devoted by her for Science and Mathematics = 2 4/5 = 14/5 hr Thus, time devoted by her for other subjects =17/3 – 14/5 hr17 * 5 / 15 – 14 * 3/ 15= 43/15 hr = 2 13/15 hr Q.3 Ritu ate 3/5 part of an apple and the remaining apple was eaten by her brother Somu. How much part of the apple did Somu eat? A) 2/4 part B) 2/5 part C) 2/6 part D) 2/7 part Ans. BThe part eaten by her brother Somu =?Who eat the larger part of apple?The larger part of apple was how much larger?The part of apple left after eaten by RituTherefore, Somu ate 2/5 parts of apple.Now compare the part eaten by them Since, 3>2. Therefore, That means Ritu ate larger part.The difference in both parts Thus,Somu ate 2/5 part of apple.Ritu ate the larger part of appleRitu ate 1/5 part more apple than her brother Somu. Q.4 The denominator of a rational number is greater than its numerator by 8. If the numerator is increased by 17 and the denominator is decreased by 1, the number obtained is 3/2.Find the rational number ? A) 13/ 21 B) 13/20 C) 11/21 D) 11/ 20 Ans. A Acc. to the question, 2(x + 17) = 3(x + 7)⇒ 2x + 34 = 3x + 21⇒ 34 − 21 = 3x − 2x⇒13 = xNumerator of the rational number = x = 13Denominator of the rational number = x + 8 = 13 + 8 = 21

Q.1 There are 2401 students in a school. P.T. teacher wants them to stand in rows and columns such that the number of rows is equal to the number of columns. Find the number of rows. A) 45 B) 47 C) 49 D) 51 Ans. C Let the number of rows be xSo, the number of columns = xTherefore, number of students = x × x = x2Thus, x2 = 2401 gives x = Sq. root of 2401 = 49The number of rows = 49 Q.2 Saili plants 4 saplings, in a row, in her garden. The distance between two adjacent saplings is ¾ m. Find the distance between the first and the last sapling A) 3 m B) 4 m C) 5 m D) 6 m Ans. A With 4 saplings there are 3 gaps: between 1 and 2, 2 and 3, and 3 & 43(3/4 m) = 9/4 m = 2.25 m Q.3 Salil wants to put a picture in a frame. The picture is 7 3/5 cm wide. To fit in the frame the picture cannot be more than 7 3/10 cm wide. How much should the picture be trimmed ? A) 3/9 B) 2/10 C) 3/10 D) 2/9 Ans. C Therefore, picture to be trimmed Thus picture should be trimmed by 3/10 cm Q.4 Ritu ate 3/5 part of an apple and the remaining apple was eaten by her brother Somu. How much part of the apple did Somu eat? A) 2/4 part B) 2/5 part C) 2/6 part D) 2/7 part Ans. BThe part eaten by her brother Somu =?Who eat the larger part of apple?The larger part of apple was how much larger?The part of apple left after eaten by RituTherefore, Somu ate 2/5 parts of apple.Now compare the part eaten by them Since, 3>2. Therefore, That means Ritu ate larger part.The difference in both parts Thus,Somu ate 2/5 part of apple.Ritu ate the larger part of appleRitu ate 1/5 part more apple than her brother Somu. Q.5 Half of a herd of deer are grazing in the field and three fourths of the remaining are playing nearby. The rest 9 are drinking water from the pond. Find the number of deer in the herd. A) 70 B) 71 C) 72 D) 73 Ans. C let x be total no. of deer, x/2 be half of the herd, 3/4{x/2} be three fourth of remaining half, so, x/2 + 3/4{(x/2} + 9 = x x/2 + 3x/8 + 9 = x 8x/8 – 4x/8 – 3x/8 = 9 x/8 = 9 x = 72

Q.1 Hasan buys two kinds of cloth materials for school uniforms, shirt material that costs him Rs 50 per metre and trouser material that costs him Rs 90 per metre. For every 3 meters of the shirt material he buys 2 metres of the trouser material. He sells the materials at 12% and 10% profit respectively. His total sale is Rs 36,600. How much trouser material did he buy? A) 198 m B) 199 m C) 200 m D) 201 m Ans. C Let 2x m of trouser material and 3x m of shirt material be bought by him.Per metre selling price of trouser material = = Rs 100.80Per metre selling price of shirt material = = Rs 55Given that, total amount of selling = Rs 36660100.80 × (2x) + 55 × (3x) = 36660201.60x + 165x = 36660366.60x = 36660Dividing both sides by 366.60, we obtainx = 100Trouser material = 2x m = (2 × 100) m = 200 m Q.2 The organisers of an essay competition decide that a winner in the competition gets a prize of Rs 100 and a participant who does not win gets a prize of Rs 25. The total prize money distributed is Rs 3,000. Find the number of winners, if the total number of participants is 63. A) 16 B) 17 C) 18 D) 19 Ans. D Let the number of winners be x. Therefore, the number of participants who did not win will be 63 – x.Amount given to the winners = Rs (100 × x) = Rs 100xAmount given to the participants who did not win = Rs [25(63 – x)]= Rs (1575 – 25x)According to the given question,100x + 1575 – 25x = 3000On transposing 1575 to R.H.S, we obtain75x = 3000 – 157575x = 1425On dividing both sides by 75, we obtainx = 19Hence, number of winners = 19 Q.3 Lakshmi is a cashier in a bank. She has currency notes of denominations Rs 100, Rs 50 and Rs 10, respectively. The ratio of the number of these notes is 2:3:5. The total cash with Lakshmi is Rs 4,00,000. How many notes of each denomination does she have? A) Rs. 10 notes= 5000 , Rs.50 notes = 3000 , Rs. 100 notes = 2000 B) Rs. 10 notes = 5000 , Rs. 50 notes = 3000 , Rs. 100 notes = 1000 C) Rs. 10 notes = 5000 , Rs. 50 notes = 3000 , Rs. 100 notes = 2500 D) Rs. 10 notes = 5000 , Rs. 50 notes = 3000 , Rs. 100 notes = 1500 Ans. A Let the common ratio between the numbers of notes of different denominations be x. Therefore, numbers of Rs 100 notes, Rs 50 notes, and Rs 10 notes will be2x, 3x, and 5x respectively.Amount of Rs 100 notes = Rs (100 × 2x) = Rs 200xAmount of Rs 50 notes = Rs (50 × 3x)= Rs 150xAmount of Rs 10 notes = Rs (10 × 5x) = Rs 50xIt is given that total amount is Rs 400000.? 200x + 150x + 50x = 400000? 400x = 400000On dividing both sides by 400, we obtainx = 1000Number of Rs 100 notes = 2x = 2 × 1000 = 2000Number of Rs 50 notes = 3x = 3 × 1000 = 3000Number of Rs 10 notes = 5x = 5 × 1000 = 5000 Q.4 A person has only Rs. 1 and Rs. 2 coins with her. If the total number of coins that she has is 50 and the amount of money with her is Rs. 75, then the number of Rs. 1 and Rs. 2 coins are, respectively A) 15 and 35 B) 35 and 15 C) 30 and 20 D) 25 and 25 Ans. D 25 and 25Assume no. of Rs 1 coins = x and no. of Rs 1 coins = yx + y = 50 (given)x + 2y = 75 (total money)hence x = 25 and y = 25 Q.5 In a queue, Mr. X is fourteenth from the front and Mr. Y is seventeenth from the end, while Mr. Z is exactly in between Mr. X and Mr. Y. If Mr. X is ahead of Mr. Y and there are 48 persons in the queue, how many persons are there between Mr. X and Mr. Z ? A) 6 B) 7 C) 8 D) 9 Ans. C +*******************+16X(14th) 8 Z(in Middle) 8 (17th)Required no. of persons between Mr. X & Mr. Z= 8

Q.1 In a rare coin collection, there is one gold coin for every three non-gold coins. 10 more gold coins are added to the collection and the ratio of gold coins to non-gold coins would be 1: 2. Based on the information; the total number of corns in the collection now becomes A) 90 B) 80 C) 60 D) 50Ans. ALet the no,of Gold coins be X & non-gold coins be 3x.As per the question-X+10/3x = ½2(x+10)= 3x2x+20 = 3xTherefore, x= 20Now, total no. of coins in the collection:=(x+10)+3x=20+10+3*2030+60=90 Q.2 A gardener has 1000 plants: He wants to plant them in such a way that the number of rows and the number of columns remains the same. What is the minimum number of plants that he needs more for this purpose?A) 14 B) 24 C) 32 D) 34Ans. BMinimum no. of plants=(32)2 – 10001024-1000=24 Q.3 A sum of RS. 700 has to be used to give seven cash prizes to the students of a school for their overall academic performance. If each prize is RS. 20 less than its preceding prize, what is the least value of the prize? A) RS. 30 B) RS. 40 C) RS. 60 D) RS. 80Ans. BLet the least value of the prize will be Rs. XThen as per question,X+(x+20) +(x+40) + (x+60) + (x+80) + (x+100) + (x+120)=7007x + 420=7007x=700-4207x= 280X=280/7 = 40 Ans. Q.4 Four friends, A, B, C and D distribute some money among themselves in such a manner that A gets one less than B, C gets 5 more than D, D gets 3 more than B. Who gets the smallest amount?A) A B) B C) C D) DAns. ALet the amount distribute in four friends A,B,C & Di.e.A–? XB—> x+1D–? (x+1) + 3 -? (x+4)C–? (x+4) +5 —? (x+9)Hence, A gets the smallest amount Q.5 A, B, C, D and E belong to five different cities P, Q, R, S and T (not necessarily in that order). Each one of them comes from a different city. Further it is given that: 1. Band C do not belong to Q. 2. Band E do not belong to P and R. 3. A and C do not belong to R, Sand T. 4. D and E do not belong to Q and T. Which one of the following statements is not correct? A) C belongs to P B) D belongs to R C) A belongs to Q D) B belongs to SAns. D

Q.1 There are some balls of red, green and yellow colour lying on a table. There are as many red balls as there are yellow balls. There are twice as many yellow balls as there are green ones. The number of red balls A) is equal to the sum of yellow and green balls. B) is double the number of green balls. C) is equal to yellow balls minus green balls. D) cannot be ascertained.Ans. BLet the no. of green balls are X.Then yellow balls will be 2x & also the red balls.Hence, the no. of red balls is double the no. of green ballds. Q.2 In a class of 45 students, a boy is ranked 20th. When two boys joined, his rank was dropped by one. What is his new rank from the end? A) 25th B) 26th C) 27th D) 28thAns. C(45+2) – (20+1) + 1= 47-21+1=48-21 = 27th Q.3 A factory employes skilled workers, unskilled workers & clerks in the ratio of 8 : 5 : 1 & the wages of a skilled worker , an unskilled worker & a clerk are in the ratio of 5 : 2 : 3. When 20 unskilled workers are employed the total daily wages of all amount to Rs. 318. Find out the daily wages paid to each category of employees ?A) Unskilled worker= Rs.3 , Skilled worker= Rs.7.50 , Clerk= Rs. 4.50B) Unskilled worker= Rs.4 , Skilled worker= Rs. 8.50 , Clerk= Rs.5.50C) Unskilled worker= Rs.5 , Skilled worker= Rs.9.50 , Clerk= Rs.6.50D) Unskilled worker= Rs.6 , Skilled worker= Rs.10.50 , Clerk= Rs.7.50Ans. A Q.4 Six faces of a cube numbered from 1 to 6, each face carrying one different number.1) Face 2 is opposite to the face 62) Face 1 is opposite to face 53) Face 3 is opposite to face 1 & face 54) face 4 is adjacent to face 2Which of the following is correct ?A) Face 6 is between face 2 & face 4B) Face 2 is adjacent to face 3C) face 1 is between the face 5 & face 6D) None of the aboveAns. B3 & 4 are opposite to each other.Since 2 is adjacent of 4, hence it must be adjacent of 3 Q.5 A college starts from 10 a.m. & continues till 1:30 p.m. In this duration there are 5 periods . If 5 min are provided before each period to leave the room & enter the other, then what is the duration of each period ? A) 41 minB) 42 min.C) 40 minD) 38 min.Ans. DDuration of college time=1:30 pm – 10:00 am= 13:30 – 10:003:30 hourOr 210 min.Time left= 5 * 4 = 20minTherefore,Time for 5 periods = 210 – 20 = 190 min.Therefore,Duration of 1 period= 190/5 = 38 min

PASASAGE:An airline has a certain free luggage allowance & charges for excess luggage at a fixed rate per kg. Two passengers Raja & Praja have 60 kg of luggage between them, and are charged Rs.1200 & Rs.2400 for excess luggage. Had the entire luggage belonged to one of them , the excess luggage charge would have been Rs. 5400. Q.1 What is the weight of the Praja’s luggage ?A) 20 kgB) 35 kgC) 40 kgD) 30 kgAns. BLet free luggage allowed be x kgRaja & Praja are allowed free luggage of 2xkgLet charge for excess luggage= Rs. Y /kgRaja & Praja pay Rs. 1200 + Rs. 2400 = 3600 excess luggageY(60-2x) = 3600–iIf entire luggage had belonged to one of them , excess luggage charges would have been Rs.5400Y (60-x) = 5400—iiFrom these two equations:60y- 2xy = 360060y – xy =5400Now. Solve these two equations;Y = 120X = 15 kgSince Praja is charged Rs.2400 for excess luggage is 2400/120 = 20kgHence weight of Praja’s luggage + her excess luggage= 15 + 20kg=35 kg Q.2 What is the free luggage allowance per person ?A) 10 kgB) 15 kgC) 20 kgD) 30 kgAns. B Q.3 Two boys begin together to write out a booklet containing 8190 lines. The first boy starts with the first line , writing at the rate of 200 lines an hour & the second boy starts with the last line, then writes 8189th line & so on, proceeding backward at the rate of 150 lines an hour. At what line will they meet ?A) 4910B) 4680C) 4280D) 5200Ans. BRelative speed = 200 + 150 = 350 lines/hrSo, they will meet after =8190 / 350 = 117/5 hrsTherefore, they will meet at 117/5*200 = 4680th line from the beginning Q.4 If 20% of P = 30% of Q = 1/6 of R, then P:Q:R is:A) 3 : 2: 16B) 2 :3 : 16C) 15 : 10 : 18D) 10 : 15 : 18Ans. CPQR=1/5:3/10:1/6=15:10:18 Q.5 A local train is going from Delhi to Saharanpur & it has 4 stoppages in between. If two passengers enter in the train during the journey , how many different sets of tickets they may had ? A) 90 B) 120 C) 45 D) 180 Ans. C 1st station = 4tickets 2nd station = 3 tickets 3rd station = 2 tickets 4th station = 1 ticket Total no. of tickets = 4+3+2+1 = 10 Therefore, sets of ticket they may had = 10C2 = 45

Q.1 If the king gave less than 100 gold coins on the whole to this sons, what is the maximum number of sons he could have had ? A) 7 B) 10 C) 11 D) 8 Ans. D On similar lines as in Q1, we add on the series with the increasing differenceThe sum of the series = 1+2+4+7+11+16+22+29 = 92 which is less than 100So, a maximum of 8 sons Q.2 A man engaged a servant on a condition that he will pay Rs 90 and also give him a bag at the end of the yr. He served for 9 months and was given a turban and Rs 65. So the price of turban is. A) 10 B) 9 C) 19 D) 50 Ans. A (90+B)/12=(65+T)/9=>270+3B=260+4T=>3B+10=4T=>T=10 Q.3 A man fills a basket with eggs in such a way that the number of eggs added on each successively day is same as the number already present in the basket. This way the basket gets completely filled in 24 days. After how many days basket was 1/4th full ? A) 6 B) 17 C) 22 D) 12 Ans. C It is written in 23rd day it was half fill & on 22nd day it was ¼ filled Q.4 A lady buys goods worth Rs.200 from a shop (shopkeeper sells the goods with zero profit). The lady gives him Rs.1000 note. The shopkeeper gets the change from the next shop and keeps 200 for himself and returns 800 to the lady. Later the shopkeeper of the next shop comes with 1000 rs note saying that it’s a duplicate and takes his money back. How much loss did the shopkeeper face? A) 1200 B) 1800 C) 1000 D) 2000 Ans. D Shopkeeper gives Rs 800 and goods which worths Rs 200 to that lady And he gives Rs1000 to his next shopkeeper So, Rs2000 Loss Q.5 A schoolyard contains only bicycles and 4 wheeled wagons. On Tuesday, the total number of wheels in the schoolyard was 90. What could be possible number of bicycles? A) 11 B) 12 C) 14 D) 10 Ans. A

Q.1 There is a pie to be divided among 20 people. A man eats 3 pizza, a women eats two pieces and a child eats half a piece of pie. Find the number of men, women and children so that they are 20 people in total and everyone gets some pie. There are 20 pieces of pie in all. A) 7 women, 1 men and 12 children B) 5 women, 1 men and 14 children C) 6 women, 2 men and 12 children D) 4women, 2 men and 14 children Ans. B Suppose for men x, women y & children z, 3x+2y+0.5z=20x=1,y=5,z=14 On looking into options,1.90-11*2 = 68,2.90-12*2=66,3.90-14*2=62,4.90-10*2=70, from this only 68 is divisible by 4 ,hence Ans. is 11 Q.2 Raman was given some money by his father on his birthday. Raman spent all of it in five stores. In each store he spent one rupee more than half of what he had when he came in. How much did he get from his father ?A) Rs. 30B) Rs. 25C) Rs. 46D) Rs. 62Ans. DJust take the options & follow acc to the question as follows :Stores Exp. Remaining amount1) Rs.62 62/2+1=32 Rs.302) Rs.30 30/2+1=16 Rs.143) Rs. 14 14/2+1=8 Rs.64) Rs.6 6/2+1=4 Rs.25) Rs.2 2/2+1=2 Rs.0 Q.3 A parcel weighing 12 kg is to be sent from New Delhi to Mumbai a distance of 1450 km.The Parcel Postage Rates are shown in the following table: Distance Category Rate upto to 2 kg INR For every additional kg over 2 kg INRLocal 35 5Upto 500 km 50 8501 to 1000 km 60 1210001 to 2000 km 70 25More than 2000 km 90 35 How much will it cost to send the parcel ? A) 85 INR B) 95 INR C) 320 INR D) 840 INR Ans. C Weight of the parcel sentfrom New Delhi to Mumbai = 12 kgDistance between New Delhi and Mumbai = 1450 km Q.4 This distance lies in the distance category 1001-2000 km. So, the cost to send 12 kg parcel would be the cost of sending a 2 kg parcel at Rs 70 plus the cost for every additional kg over 2 kg i.e. atRs 25 /kg.Thus, cost of sending the parcel = Rs 70 + (12–2) kg × Rs 25/kg = Rs 70 + Rs 10 × 25 = Rs 320 PASSAGE: There are 128 cubes with me which are coloured according to two schemes viz.64 cubes each having two red adjacent faces and one yellow and other blue on their opposite faces while green on the rest.64 cubes each having two adjacent blue faces and one red and other green on their opposite faces, while red on the rest. They are then mixed up. Q.5 How many cubes have at least two coloured red faces each ?A) 0B) 32C) 64D) 128Ans. D64 and 64 cubes of both types of cubes are such who have at least two coloured faces red each.Therefore, total number of the required cubes is 128 Q.6 What is the total number of red faces ?A) 0B) 320C) 128D) 64Ans. BNo. of red faces among first 64 cubes = 128No. of red faces among second 64 cubes = 192Therefore, total number of red faces = 128 + 192 = 320 Q.7 How many cubes have two adjacent blue faces each ?A) 0B) 64C) 32D) 128Ans. BSecond 64 cubes are such each of whose two faces are blue. Q.8 How many cubes have only one red face each ?A) 128 B) 32C) 64D) None of the aboveAns. DOut of 128 cubes no cube have only one face is red Q.9 Which two colours have the same number of faces ?A) Red and YellowB) Blue and GreenC) Red and GreenD) Red and BlueAns. BFirst 64 cubes are such each of whose two faces are green and second 64 cubes are such each of whose two faces are blue.

Q.1 In a row of children Rohan is seventh from the left & Bali is fourth from the right. When Rohan & Bali exchange their position, Rohan will be fifteenth from the left. Bali’s position from the right will be ? A) 4th B) 12th C) 11th D) 8th Ans. BIst case: 1  2  3  4  5  6  7             8  9                          Rohan10  11  12  13  14  15  16  17  18                             Bali2nd case:         1  2  3  4  5  6  7          8   9                                 Bali                         Rohan  12      11  10 10  11  12  13 14   15       16   17  189     8     7    6   5     4        3      2    1 Q.2 Mr. Vajpayee M.D. of X,Y,Z company asked five persons -Asit,Varun,Chandra,Danny & Eshita about their interest in a new project. He got following replies: Asit: None of us is interested Varun : One of us is interested Chandra : Two of us are interested Danny : Three of us are interested Eshita : Four of us are interested From his experience Mr. Vajpayee knows that those who are interested only tells the truth & others lie.How many of them are interested in the new project ?A) 3 B) 4 C) 2 D) 1 Ans. D Q.3 There are four roads, I have come from the South & want to go to the temple. The road to the right leads me away from the coffee house while straight road leads to a college. In which direction is the temple ? A) North B) South C) East D) west Ans. C Q.4 A cube has 6 faces each of different colour. Red face is opposite to the black. The green face is in between red & black. Blue face is adjacent to the white & brown face is adjacent to the blue. Four colours adjacent to green are : A) Red,Black,Brown & White B) Red,Brown,Blue & White C) Red,Black,Blue & White D) Red, Black , Brown & Blue Ans. A         6 (Front surface)1- Green, 2- Brown,3-Blue,4-White5- Black6-red Therefore, Green surface is following four colours- Red, Black,Brown & White Q.5 If 378 Coins consists of one rupee, 50 paise & 25 paise whose values are proportional to 13:11:7, Number of 50 paise coins will be : A) 133 B) 132 C) 128 D) 136 Ans. B 13*x+11*2x+7*4x = 378 13x+22x+28x = 378 63x = 378 X = 378/63 = 6 Therefore, Required number of 50 paise coins = 22x =22 * 6 =132

  Q.1 In a row of children Rohan is seventh from the left & Bali is fourth from the right. When Rohan & Bali exchange their position, Rohan will be fifteenth from the left. Bali’s position from the right will be ? A) 4th B) 12th C) 11th D) 8th Ans. BIst case: 1  2  3  4  5  6  7             8  9                          Rohan10  11  12  13  14  15  16  17  18                             Bali2nd case:         1  2  3  4  5  6  7          8   9                                 Bali                         Rohan  12      11  10 10  11  12  13 14   15       16   17  189     8     7    6   5     4        3      2    1 Q.2 Mr. Vajpayee M.D. of X,Y,Z company asked five persons -Asit,Varun,Chandra,Danny & Eshita about their interest in a new project. He got following replies: Asit: None of us is interested Varun : One of us is interested Chandra : Two of us are interested Danny : Three of us are interested Eshita : Four of us are interested From his experience Mr. Vajpayee knows that those who are interested only tells the truth & others lie.How many of them are interested in the new project ?A) 3 B) 4 C) 2 D) 1 Ans. D Q.3 There are four roads, I have come from the South & want to go to the temple. The road to the right leads me away from the coffee house while straight road leads to a college. In which direction is the temple ? A) North B) South C) East D) west Ans. C Q.4 A cube has 6 faces each of different colour. Red face is opposite to the black. The green face is in between red & black. Blue face is adjacent to the white & brown face is adjacent to the blue. Four colours adjacent to green are : A) Red,Black,Brown & White B) Red,Brown,Blue & White C) Red,Black,Blue & White D) Red, Black , Brown & Blue Ans. A         6 (Front surface)1- Green, 2- Brown,3-Blue,4-White5- Black6-red Therefore, Green surface is following four colours- Red, Black,Brown & White Q.5 If 378 Coins consists of one rupee, 50 paise & 25 paise whose values are proportional to 13:11:7, Number of 50 paise coins will be : A) 133 B) 132 C) 128 D) 136 Ans. B13*x+11*2x+7*4x = 378 13x+22x+28x = 378 63x = 378 X = 378/63 = 6 Therefore, Required number of 50 paise coins = 22x =22 * 6 =132