Q.1 There is a pie to be divided among 20 people. A man eats 3 pizza, a women eats two pieces and a child eats half a piece of pie. Find the number of men, women and children so that they are 20 people in total and everyone gets some pie. There are 20 pieces of pie in all.

A) 7 women, 1 men and 12 children

B) 5 women, 1 men and 14 children

C) 6 women, 2 men and 12 children

D) 4women, 2 men and 14 children

Ans. B

Suppose for men x, women y & children z,

3x+2y+0.5z=20

x=1,y=5,z=14

On looking into options,

1.90-11*2 = 68,

2.90-12*2=66,

3.90-14*2=62,

4.90-10*2=70,

from this only 68 is divisible by 4 ,hence Ans. is 11

Q.2 Raman was given some money by his father on his birthday. Raman spent all of it in five stores. In each store he spent one rupee more than half of what he had when he came in. How much did he get from his father ?

A) Rs. 30

B) Rs. 25

C) Rs. 46

D) Rs. 62

Ans. D

Just take the options & follow acc to the question as follows :

Stores Exp. Remaining amount

1) Rs.62 62/2+1=32 Rs.30

2) Rs.30 30/2+1=16 Rs.14

3) Rs. 14 14/2+1=8 Rs.6

4) Rs.6 6/2+1=4 Rs.2

5) Rs.2 2/2+1=2 Rs.0

Q.3 A parcel weighing 12 kg is to be sent from New Delhi to Mumbai a distance of 1450 km.

The Parcel Postage Rates are shown in the following table:

Distance Category Rate upto to 2 kg INR For every additional kg over 2 kg INR

Local 35 5

Upto 500 km 50 8

501 to 1000 km 60 12

10001 to 2000 km 70 25

More than 2000 km 90 35

How much will it cost to send the parcel ?

A) 85 INR

B) 95 INR

C) 320 INR

D) 840 INR

Ans. C

Weight of the parcel sent

from New Delhi to Mumbai = 12 kg

Distance between New Delhi and Mumbai = 1450 km

Q.4 This distance lies in the distance category 1001-2000 km. So, the cost to send 12 kg parcel would be the cost of sending a 2 kg parcel at Rs 70 plus the cost for every additional kg over 2 kg i.e. at

Rs 25 /kg.

Thus, cost of sending the parcel = Rs 70 + (12

–

2) kg × Rs 25/kg = Rs 70 + Rs 10 × 25 = Rs 320

PASSAGE:

There are 128 cubes with me which are coloured according to two schemes viz.

64 cubes each having two red adjacent faces and one yellow and other blue on their opposite faces while green on the rest.

64 cubes each having two adjacent blue faces and one red and other green on their opposite faces, while red on the rest. They are then mixed up.

Q.5 How many cubes have at least two coloured red faces each ?

A) 0

B) 32

C) 64

D) 128

Ans. D

64 and 64 cubes of both types of cubes are such who have at least two coloured faces red each.

Therefore, total number of the required cubes is 128

Q.6 What is the total number of red faces ?

A) 0

B) 320

C) 128

D) 64

Ans. B

No. of red faces among first 64 cubes = 128

No. of red faces among second 64 cubes = 192

Therefore, total number of red faces = 128 + 192 = 320

Q.7 How many cubes have two adjacent blue faces each ?

A) 0

B) 64

C) 32

D) 128

Ans. B

Second 64 cubes are such each of whose two faces are blue.

Q.8 How many cubes have only one red face each ?

A) 128

B) 32

C) 64

D) None of the above

Ans. D

Out of 128 cubes no cube have only one face is red

Q.9 Which two colours have the same number of faces ?

A) Red and Yellow

B) Blue and Green

C) Red and Green

D) Red and Blue

Ans. B

First 64 cubes are such each of whose two faces are green and second 64 cubes are such each of whose two faces are blue.