Q.1 Two men A & B walk simultaneously from Point Q, a distance of 210m at the speed 30km/hr & 40km/hr respect to B reaches Q, returns immediately & meets A at R. Find the distance from P to R ?

A) 18 km

B) 19 km

C) 20 km

D) 21 km

Ans. A

Distance travelled by A= 2*distance between the two points * ( a/a+b)

Distance travelled by B = 2 * distance between the two points * (a / a+b)

Therefore, distance travelled by A = 2 * 210 / 30 / 10

= 18 km

Q.2 A man covers a certain distance by the car driving at 70km/hr & he returns back to the starting point riding on a scooter at 55km/hr. Find the speed ?

A) 61.6

B) 62.5

C) 63.6

D) 64.5

Ans. A

2 * s1 * s2 / s1 + s2

2 * 70 * 55 / 70 + 55

= 61.6 km/hr

Q.3 A person covers 10km. At 4km/hr & then travels further 21km at 6 km/hr. Find his average speed for the total journey ?

A) 31 / 6

B) 32 / 6

C) 33 /6

D) 34 / 6

Ans. A

T1 = 10 / 4 = 5 / 2

T2 = 21 / 6 = 7 / 2

Total time = 5/2 + 7/2 = 12 / 2

= 6 hrs

Now, Average speed = 21 + 10 / 6

= 31 / 6

Q.4 A person travelled a distance of 50 km in 8 hr. He covered a part of the distance on the foot at the rate of 4 km/hr & a part on a bicycle at the rate of 10 km/hr. How much distance did he travel on foot?

A) 10 km

B) 20 km

C) 30 km

D) 40 km

Ans. B

Let x hour he travel by foot

4x + 10(8-x) = 50

80 – 6x = 50

6x = 30, x=5 hr

Now putting in place of x, we get distance

Q.5 Two cars X & Y start from two places A & B which are 700 km apart at 9:00 am. Both the cars runs at an average speed of 60 km/hr. Car X stops at 10:00 am while the other car Y continues to run without stopping. When the two cars cross each other ?

A) 4:20 pm

B) 3:20 pm

C) 4:10 pm

D) 2:40 pm

Ans. A

Since speed of X & Y are 60km/hr

Distance b/w A & B is 700 km

Distance travelled by X upto 10 am is 60 km

since x stops at 10:00 am & distance travelled by Y upto 11 am is 120 km

Now the distance between them = 700-180 = 520 km

Now, let they will meet at a distance of x from X’s position

Therefore, distance travelled by x = x km

& distance travelled by y = 520-x km

Therefore, x/60 = 520-x/60

2x = 520

X = 260

Or t = 260/60 = 4 1/3

Thus they will cross each other after 4 1/3hrs after 11:00 am

3:20 pm