Q.1 Two men A & B walk simultaneously from Point Q, a distance of 210m at the speed 30km/hr & 40km/hr respect to B reaches Q, returns immediately & meets A at R. Find the distance from P to R ?
A) 18 km
B) 19 km
C) 20 km
D) 21 km
Ans. A
Distance travelled by A= 2*distance between the two points * ( a/a+b)
Distance travelled by B = 2 * distance between the two points * (a / a+b)
Therefore, distance travelled by A = 2 * 210 / 30 / 10
= 18 km
Q.2 A man covers a certain distance by the car driving at 70km/hr & he returns back to the starting point riding on a scooter at 55km/hr. Find the speed ?
A) 61.6
B) 62.5
C) 63.6
D) 64.5
Ans. A
2 * s1 * s2 / s1 + s2
2 * 70 * 55 / 70 + 55
= 61.6 km/hr
Q.3 A person covers 10km. At 4km/hr & then travels further 21km at 6 km/hr. Find his average speed for the total journey ?
A) 31 / 6
B) 32 / 6
C) 33 /6
D) 34 / 6
Ans. A
T1 = 10 / 4 = 5 / 2
T2 = 21 / 6 = 7 / 2
Total time = 5/2 + 7/2 = 12 / 2
= 6 hrs
Now, Average speed = 21 + 10 / 6
= 31 / 6
Q.4 A person travelled a distance of 50 km in 8 hr. He covered a part of the distance on the foot at the rate of 4 km/hr & a part on a bicycle at the rate of 10 km/hr. How much distance did he travel on foot?
A) 10 km
B) 20 km
C) 30 km
D) 40 km
Ans. B
Let x hour he travel by foot
4x + 10(8-x) = 50
80 – 6x = 50
6x = 30, x=5 hr
Now putting in place of x, we get distance
Q.5 Two cars X & Y start from two places A & B which are 700 km apart at 9:00 am. Both the cars runs at an average speed of 60 km/hr. Car X stops at 10:00 am while the other car Y continues to run without stopping. When the two cars cross each other ?
A) 4:20 pm
B) 3:20 pm
C) 4:10 pm
D) 2:40 pm
Ans. A
Since speed of X & Y are 60km/hr
Distance b/w A & B is 700 km
Distance travelled by X upto 10 am is 60 km
since x stops at 10:00 am & distance travelled by Y upto 11 am is 120 km
Now the distance between them = 700-180 = 520 km
Now, let they will meet at a distance of x from X’s position
Therefore, distance travelled by x = x km
& distance travelled by y = 520-x km
Therefore, x/60 = 520-x/60
2x = 520
X = 260
Or t = 260/60 = 4 1/3
Thus they will cross each other after 4 1/3hrs after 11:00 am
3:20 pm
