Q.1 A bus left point X for point Y. two hours later a car left point X for Y and arrived at the same time as the bus. If the car and bus left simultaneously from the opposite ends X and Y towards each other they would meet 1.33 hours after the start . How much time did the bus take to travel from X to Y

A) 2hr

B) 6hr

C) 4hr

D) 8hr

Ans. C

Q.2 Sardar khan went out wasseypur at 10:00 am at a speed of 50km/hr. Ramadhir finds out about it at 11:00 am & sends his man to kill sardar khan. Ramadhir’s men travels at a speed of 60km/hr. What will be the distance between them 1hr before they meet & at what time they will meet ?

A) Distance- 10 km , time-4 pm

B) Distance- 11 km , time-5 pm

C) Distance- 11.5 km , time-5.30 pm

D) Distance-12 km , time- 6 pm

Ans. A

11 am sardar khan would be 50km

12pm he would be 100km

1pm he would be 150km

Now,

11am ramadhir men (gap=50km)

12pm Ramadhir men would be 60km (gap=40km)

1pm Ramadhir men would be 120km (gap=30km)

Therefore,

Relative speed =60-50 = 10km/hr

Or 50/10 = 5hr

Now calculate 5hr from 11am; i.e. 4pm

Distance between them = 10km

Q.3 A man sets out to cycle from Delhi to Rohtak & at the same time another man starts from Rohtak to delhi on cycle. After passing each other they complete their journey in 3 1/3 & 4 4/5hrs. At what rate does the second man cycle if the first cycles at 8km/hr ?

A) 6 2/3

B) 7 2/3

C) 8 2/3

D) 9 2/3

Ans. A

If two persons start from same time in opposite direction from two points, then

A’s speed : B’s speed = vb : va

8 /3 = v4 4/5 / v3 9/3

= 6/5

Or B’s speed = 8*5/6 = 6 2/3

Q.4 When a person covers a distance between his house & office at 50km/hr he is late by 20 min. but when he travels at 60km/hr he reaches 10min. early. What is the distance between his house & office ?

A) 150

B) 160

C) 170

D) 180

Ans. A

Product of speed / difference of speed * difference between arrival time

60*50 / 60-50 * 60 / 60

150

Q.5 Running at 5/4 of his usual speed an athlete improves his timing by 5 min.How much time he usually takes to run the same distance ?

A) 25 min.

B) 26 min.

C) 27 min.

D) 28 min.

Ans. A

Usual time = Improvement in time / 1- old speed/new speed

5 / 1-1/ 5/4

5/ 1-4/5

=5/ 1/5

=25min.