Q.1 A monkey climbed up greased pole ascends 10 metres & slips 2 metres in an alternate min. If the pole is 56 metres high, how long will it take him to reach the top ?

A) 12 min.

B) 12.8 min.

C) 8 min.

D) Can’t be determined

Ans. B

10 m and – 2m in total 2 minutes => Net height climbed = 10-2 = 8 m in 2 minutes = 4m/ min.

In 14 minutes he will cover 14*4 = 56 m.

Now, in the next minute he will cover 10m in ‘1’ min.

=> Speed = 10/60 m/sec.

He has to cover 64-56 = 8 metres more.

Time taken to cover these 8m = 8/(10/60) = 48 seconds.

Q.2 Hemant rides at the rate of the 10 km/hr but stops for 10 min.to take rest at the end of every 15 km. How long will he take to go a distance of 100 km ?

A) 10 hrs

B) 12 hrs

C) 11 hrs

D) 14 hrs

Ans. C

He will take rest = 100/15 = 6 times

Time taking in taking rest = 6*10 = 60 min. = 1 hr

Time taken to cover the distance = 100/10 = 10 hrs

Total time = 1+10 = 11 hrs

Q.3 A car travels 25 km an hour faster than a bus & takes 10 hrs less for a journey of 500km. the speed of the car & bus are :

A) 60 & 35

B) 50 & 55

C) 70 & 45

D) 80 & 55

Ans. B

Let speed of car be x km/hr

Therefore speed of bus = x-25 km/hr

500/x-25 – 500/x = 10

500 (x – x + 25)/ x (x-25) = 10

500 * 25 = 10x (x – 25)

(x – 25)x = 50 * 25

Therefore, x=50 km/hr & x – 25 =25 km/hr

Q.4 A goods train starts from the Bombay to Nandgaon & runs at a speed of 32 km/hr. Three hours later, passenger train also starts from the Bombay & reaches Nandgaon at the same time as the goods train. If the speed of the passanger train exceeds the speed of the goods train by 16km/hr. What is the distance between Bombay & Nandgaon ?

A) 330 km

B) 250 km

C) 412 km

D) 288 km

Ans. D

Distance covered by the goods train in 3 hrs = 32*3 = 96 km

Relative speed of passanger train = 16 km/hr

& speed = distance /Time

16 = 96/Time

Time = 6hrs

Speed of the passenger train = 32 + 16 = 48km/hr

Therefore, Distance between Bombay & Nandgaon = 48 * 6

= 288 km

Q.5 Two trains leave Delhi at the same time . One travels North at 60 Km/hr & the other travels South at 40 km/hr. After how many hours will the trains be 150 km apart ?

A) 4/3

B) 3/4

C) 15/2

D) 3/2

Ans. D

Relative speed = 60 + 40 = 100

Time = Distance / Speed

= 150/100 = 3/2 hr

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