Q.1 In a survey it was found that 40 % like tea,50% like coffee , 60% like milk. Every person likes atleast one of the thrice items tea/coffee/milk. What are the maximum & minimum possible values who like all the three ?
A) 25 & 50
B) 50 & 25
C) 30 & 60
D) 60 & 30
Ans. A
Maximum value = Surplus/2
Or Surplus = 40+50+60 = 150/3
Surplus=50
Or 50/2=25
Minimum Value
= Surplus = 50 Ans.
Q.2 In a survey it was found 80% like tea & 70 % like coffee. What is the minimum number of those who like this ?
A) 50
B) 60
C) 70
D)80
Ans. A
A U B = n A + n B – n(A n B)
Or 100 = 80+70-n(A n B)
n (A n B) = 150-100 = 50
Q.3 In two successive years 104 & 96 students of a school appeared at the final examination & 75% & 87 ½ % passed. The average % of the passing is :-
A) 80 %
B) 81 %
C) 82 %
D) 83 %
Ans. B
% of passing = Total passing / Total students * 100
Students passed in Ist year = 104*75/100 = 78
Students passed in IInd year = 96*87.5/100 = 84
Therefore, total pass = 78+84 = 162
Or Total students = 104+96 = 200
Thus, according to the formula, we have
162/200*100 = 81%
Q.4 Salaries of A & B together amount Rs.2000/- A spent 95 % of his salary & B 85% of his salary . If now their savings are same. What is the A’s salary ?
A) 1500
B) 750
C) 1250
D) 1800
Ans. A
Salary of A & B together Rs. 2000/-
Let A’s salary =x then B’s salary = (2000-x)
Expenditure of A = 95% of x
Savings of A = 5% of A
Savings of B=15% of (2000-x)
5% of A = 15% of B
Or 5x/100 = 15/100 (2000-x)
Or 5x = 30000-15x
20x = 30000
Or x=1500
Q.5 A’s salary is 30% more than the B’s salary. B’s salary is 40 % of C’s salary . If the total salary of A,B & C together is 7680. What is the A’s salary ?
A) 2060
B) 2070
C) 2080
D) 2090
Ans. C
Let C’s salary be 100,
B = 40/100*100 = 40X
A = 4
