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# CP & SP SET2

Q.1 Person purchases 100pens at a discount of 10%. Then net amount of money spent by the person to purchase the pens is Rs.600. The selling expenses incurred by the person are 15% on the net cost price. What would be the S.P. for 100 pens in order to earn a profit of 25% ?
A) Rs. 875
B) Rs. 811
C) Rs. 862.50
D) Rs. 802.50
Ans. C
Total cost price = 600+15% of 600
=600 + 600 * 15/100
Rs. 690
Profit = 25%
Thus, S.P.=C.P. [100+profit / 100]Or 690[100+25 / 100]
690*125/100 = Rs.862.50

Q.2 Left pan of a faulty weighs 100 gms more than its right pan. A shopkeeper keeps the weight measure in the left pan while buying goods but keeps it in the right pan while selling his goods. He uses only 1kg weight measure. If he sells his goods at the listed cost price, what is his gain % ?
A) 200/9 %
B) 100/11 %
C) 200/11 %
D) 1000/9 %
Ans. C
Let purchased amount be 1100 g & the cost price of 1100 g be Rs. x
Therefore, he pays for 1000 g & buys 1100g
Cost Price of 1000g = Rs.10/11x
Therefore, net profit = Rs.x/11
Similarly while selling if he sells 1000g.
He would actually be selling 900kg at the price of 1000kg
Similarly, once again the profit would be Rs. x/11
Therefore total profit = Rs.2x/11 * 100
In terms of percentage ,this would be 200/11%

Q.3 A man purchase 8 pens for Rs. 9 & sells 9 pens for Rs.8. How much Profit or Loss % ?

A) 20.98 %

B) -20.98%

C) 19.98 %

D) 19.98 %

Ans. B

Shortcut:

8 9

9 8

= 64-81 / 81 = -20.98 %

Since it is in negative that’s why it is Loss %

Q.4 A dishonest dealer uses a weight of 950 gm for 1 kg gain % ?

A) 5.26 %

B) 6.26 %

C) 5.30 %

D) 6.30 %

Ans. A

Shortcut:

Error / true value * 100 = 1000-950 / 1000-(1000-950) * 100

50/950 * 100

= 5.26 %

Q.5 A shopkeeper sells his product at a profit of 10 % & uses a weight which is 20 % less. What is the total gain % ?

A) 39.7 %

B) 37.5 %

C) 40.20 %

D) 36.2 %

Ans. B

Shortcut :

Gain % + % less in weight / 100 – % less in weight * 100

10+20/100-20 * 100

30/80*100 = 37.5 %