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# AGES SET-7

1. Average age of A and B is 24 years and average age of B, C and D is 22 years. The sum of the ages of A, B, C and D is
A) 90
B) 98
C) 120
D) Data is not adequate
Ans. D

2. Total of the ages of A, B ahd C at present is 90 years. Ten years ago, the ratio of their ages was 1: 2: 3. What is the age of B at present
A) 25
B) 30
C) 45
D) 60
Ans. B
Let their ages 10 years ago is x, 2x and 3x years.
10 + 2x + 10 + 3x + 10 = 90 hence x= 10
B?s present age = (2x + 10) =30 years

3. A man is 24 years older than his son. In two years, his age will be twice the age of his son. The present age of his son is
A) 20 years
B) 21 years
C) 22 years
D) 24 years
Ans. C
Let the son’s present age be x years. Then, man’s present age = (x + 24) years
=> (x + 24) + 2 = 2(x + 2)
=> x + 26 = 2x + 4
So, x = 22

4. A man is 24 years older than his son. In two years, his age will be twice the age of his son. The present age of this son is
A) 21 years
B) 22 years
C) 23 years
D) 24 years
Ans. B
Let’s Son age is x, then Father age is x+24.
=> 2(x+2) = (x+24+2)
=> 2x+4 = x+26
=> x = 22 years

5. Tanya’s grandfather was 8 times older to her 16 years ago. He would be 3 times of her age 8 years from now. What was ratio of ages of Tanya and her grandfather 8 years ago.
A) 11:50
B) 11:51
C) 11:53
D) 11:54
Ans. C
Let, Tanya age 16 years ago = x,
Grandfather’s age 16 years ago = 8x.

8 years from now, 3(x+16+8) = (8x+16+8)
=> x = 48/5

8 years ago ratio was:

=>x+88x+8=485+88×485+8=>x+88x+8=485+88×485+8=>x+88x+8=485+88×485+8

=>88424=1153=>88424=1153=>88424=1153