1. Sachin was twice as old as Ajay 10 years back. How old is Ajay today if Sachin will be 40 years old 10 years hence
A) 18
B) 25
C) 15
D) 20
Ans. D
Sachin’s age today = 30 years.
Sachin’s age 10 years back = 20 years.
Ajay’s age 10 years back = 10 years.
Ajay’s age today =20 years
2. In 10 years, A will be twice as old5as B was 10 years ago. If A is now 9 years older than B, the present age of B is
A) 35
B) 37
C) 39
D) 41
Ans. C
Let B’s age = x years.
Then, As age = (x+ 9) years.
(x+9+10)=2(x?10)
hence x=39.
Present age of B = 39 years
3. Ten years ago A was half of B in age. If the ratio of their present ages is 3 : 4, what will be the total of their present ages
A) 30
B) 35
C) 37
D) 41
Ans. B
Let A’s age 10 years ago = x years.
Then, B’s age 10 years ago = 2x years.
(x + 10) / (2x+ lO) = 3/4
=> x = 5.
So, the total of their present ages =(x + 10 + 2x + 10)
= (3x + 20) = 35 years.
4. Sushil was thrice as old as Snehal 6 years back. Sushil will be times as old as Snehal 6 years hence. How old is Snehal today
A) 12
B) 16
C) 18
D) 24
Ans. A
Let Snehals age 6 years back = x.
Then, Sushils age 6 years back = 3x.
(5/3) * (X + 6 + 6) = (3X + 6 + 6)
So 5(x+ 12) = 3(3x+ 12),
so x=6.
Snehal Age = (x+ 6) years = 12 years
5. Six years ago, the ratio of the ages of Kunal and Sagar was 6:5, Four years hence, the ratio of their ages will be 11:10. What is Sagar age at present
A) 10 years
B) 12 years
C) 14 years
D) 16 years
Ans. D
Let six years ago the age of Kunal and Sagar are 6x and 5x resp.
then,
=>(6x+6)+4(5x+6)+4=1110=>(6x+6)+4(5x+6)+4=1110=>(6x+6)+4(5x+6)+4=1110
<=>10(6x+10)=11(5x+10)<=>10(6x+10)=11(5x+10)<=>10(6x+10)=11(5x+10)
<=>5x=10=>x=2<=>5x=10=>x=2<=>5x=10=>x=2
So Sagar age is (5x+6) = 16
