Q.1 A certain no. of men complete a work in 60 days. If there were 8 men more work could be finished in 10 days less. How many men were originally there ?

A) 40

B) 41

C) 42

D) 43

Ans. A

Shortcut:

No. of more men * (60-10) / 10

8*50/10=40

Q.2 A can do work in 7 days. If A does twice as much work as B in a given time, find how long A & B would take to do the work ?

A) 4 2/4 days

B) 5 2/3 days

C) 4 2/3 days

D) 5 2/4 days

Ans. C

Shortcut:

A+B=xy/x+y

i.e. 7*14/14+7

= 4 2/3 days

Q.3 10 men can finish a work in 10 days where it takes 12 women to finish it in 10 days. If 15 men & 6 women undertake to complete the work how many days will they take to complete it ?

A) 5 days

B) 6 days

C) 7 days

D) 8 days

Ans. A

15 men=10*10/15

=20/3 days

6 women=12*10/6

=20 days

15men+6women=20/3 * 20 / 20/3+20 (we have used this formula: x*y/x+y)

20*20/80

=5 days

Q.4 A,B & C can finish a work in 10,12 & 15 days. If B stops after 2 days how long would it take to A & C to finish the remaining work ?

A) ½ work

B) 1/3 work

C) ¼ work

D) 1/5 work

Ans. A

Shortcut:

2 (1/10 + 1/15 + 1/12)

Or 2*1/4

=1/2 work

Q.5 A is twice as good as workman as B. Together they finish in 14 days. In how many days can it be done by each separately ?

A) 21 days

B) 22 days

C) 23 days

D) 24 days

Ans. A

Shortcut:

(Twice + one) = Thrice in 14 days

i.e. 14 * 3 = 42 days

or twice person = 42 / 2 = 21 days