Q.1 On a railway route between the two places A & B, there are 20 stations on the way. If 4 new stations are to be added how, many types of new tickets will be required if each ticket is issued for a one way journey ?
A) 48
B) 14
C) 108
D) 96
Ans. C
Number of stations=10+2+4 = 16
Thus for each stations number of stations for which tickets are to be issued = 15
Number of tickets for each new stations = 30
Total number of tickets = 30*4 – 4*3 = 108
Q.2 In a road network covering 10 cities, city C can be reached only from City A or B. The distance from A to C is 50km & the same from B to C is 25 km.The shortest distance from A to B is 40 km. The shortest distance from city P to A is 200 km & the shortest distance from City P to B is 230 km. Then the shortest distance from city P to C is:
A) 255 km
B) 250 km
C) 225 km
D) 265 km
Ans. B
Since city C can be reached from A or B only, P is not directly connected to city C.
From P we will have to go either to A or B, before going to city C.
i.e. PA + AC = 200 + 50 = 250 KM
Q.3 Arun, Barun & Kiranmala start from the same place & travel in the same direction at speed of 30,40 & 60 km/hr. Barun starts two hours after Arun . If Barun & Kiranmala overtake Arun at the same instant, how many hours after Arun did Kiranmala start ?
A) 3
B) 4
C) 3.5
D) 5
Ans. B
Arun covers 60 km in 2 hrs
Barun takes 60/10 = 6hrs to meet Arun
In 2+6 = 8 hrs
Arun travels 8 * 30 = 240 km
Kiranmala also overtakes both at this point
She takes 240/60 = 4hr to overtake Arun
Hence, Kiranmala starts 8-4 = 4 hrs after Arun
Q.4 I walk a certain distance & ride back & take 6 ½ hours altogether. I could walk both the ways in 7¾
Hours. How long would it take me to ride both the ways ?
A) 5 hrs 15 min.
B) 4 hrs 25 min
C) 7 hrs 8 min
D) 3 hrs 12 m in
Ans. A
Walking + riding = 13/2 hrs–i
Walking + walking = 7 ¾ hrs
Or 2 walking = 31/4 hrs—ii
2 * equation 1 – equation 2
2 riding = 13-31/4 = 21/4 5hrs 15min
Q.5 A thief is spotted by a policeman from a distance of 200 meters. When the policeman starts the chase thief also starts running. Assuming the speed of the thief 10 km an hour & that of the policeman 12 kilometers an hour , how far will have the thief run before he is overtaken ?
A) 2.5 km
B) 1 km
C) 1.5 km
D) 5 km
Ans. B
Relative speed = 12-10 = 2km/hr
Therefore the thief will be caught after = 0.2/2 = 1/10 hr
Thus distance covered by the thief before he gets caught = 10 * 1/10 = 1km
