Q.1 Doctors have advised sheetal, a chocolate freak, not to take more than 20 chocolates in one day. When she went to the market to buy her daily quota, she found that if she buys chocolates from a market complex she would have 3 Rs more for the same no. of chocolates than she would have spent. Had she bought them from her uncle scrooge’s shop , getting two sweets less per rupee. she finally decided to get them from uncle scrooge shop paying only in one rupee coins.
how many chocolates did she buy?
Let n be the number of chocolates she bought.
Price at market = 1/(x-2)
Price at Scrooge’s shop = 1/(x)
n/(x-2) = n/(x) + 3
2n = 3x(x-2)
n = 3x(x-2)/2
Now, through hit &trial method, (Just put value of X starting from 1,,,then 2,,,then 3 as so on…& you will find after putting x=4 it will calculate & comes as 12)
Q.2 How much would she have spent at the market complex?
At the market complex
n/(x-2) = 12/2 = 6
Q.3 Five farmers have 7, 9, 11, 13 & 14 apple trees, respectively in their orchards. Last year, each of them discovered that every tree in their own orchard bore exactly the same number of apples. Further, if the third farmer gives one apple to the first, and the fifth gives three to each of the second and the fourth, they would all have exactly the same number of apples. What were the yields per tree in the orchards of the third and fourth farmers?
A) 12 & 8 Apples per tree
B) 11 & 9 Apples per tree
C) 10 & 14 Apples per tree
D) 17 & 21 Apples per tree
Let a, b, c, d & e be the total number of apples bored per year in A, B, C, D & E ‘s
orchard. Given that a + 1 = b + 3 = c – 1 = d + 3 = e – 6
But the question is to find the number of apples bored per tree in C and D ‘s orchard. If is enough to consider c – 1 = d + 3.
Since the number of trees in C’s orchard is 11 and that of D’s orchard is 13. Let x
and y be the number of apples bored per tree in C & d ‘s orchard respectively.
Therefore 11 x – 1 = 13 y + 3
By trial and error method, we get the value for x and y as 11 and 9
Q.4 If a light flashes every 6 seconds, how many times will it flash in ¾ of an hour?
A) 451 times
B) 651 times
C) 751 times
D) 851 times
There are 60 minutes in an hour.
In ¾ of an hour there are (60 * ¾) minutes = 45 minutes.
In ¾ of an hour there are (60 * 45) seconds = 2700 seconds.
Light flashed for every 6 seconds.
In 2700 seconds 2700/6 = 450 times.
The count start after the first flash, the light will flashes 451 times in ¾ of an hour
Q.5 There are 3 persons Sudhir, Arvind, and Gauri. Sudhir lent cars to Arvind and Gauri as many as they had already. After some time Arvind gave as many cars to Sudhir and Gauri as many as they have. After sometime Gauri did the same thing. At the end of this transaction each one of them had 24. Find the cars each originally had ?
A) Sudhir had 39 cars, Arvind had 21 cars and Gauri had 12 cars.
B) Sudhir had 40 cars, Arvind had 30 cars & Gauri had 10 cars
C) Sudhir had 41 cars, Arvind had 40 cars & Gauri had 8 cars
D) Sudhir had 42 cars, Arvind had 50 cars & Gauri had 6 cars
Sudhir Arvind Gauri
Finally 24 24 24
Before Gauri’s transaction 12 12 48
Before Arvind’s transaction 6 42 24
Before Sudhir’ s transaction 39 21 12