2 2 6 1 0 1

# MISCELLANEOUS MCQ SET-18

Q.1 Five persons fire a bullets at a target at an interval of 6,7,8,9,& 12 seconds respectively. The no. of times they would fire the bullets together at the target in an hour is

A) 6

B) 7

C) 8

D) 9

Ans. B

Explanation:
L.C.M. of 6,7,8,9 & 12 = 504
Reqd. no. = 60*60/504
=7 times

Q.2 Assume that-
1. the hour & minute hands of a clock move without jerking.
2. the clock shows a time between 8 O’ clock & 9 O’clock.
3. the two hands of the clock are one above the other.
After how many minutes (nearest integer) will the two hands be again lying one above the other?

A) 60

B) 62

C) 65

D) 67

Ans. C

Explanation:

Reqd. time=60*60/55
=65 5/11
= 65

Q.3 A gardener increased the area of his rectangular garden by increasing its length by 40% & decreasing its width by 20%.The area of the new garden

A) has increased by 20%

B) has increased by 12%

C) has increased by 8%

D) Same as the old area

Ans. B

Explanation:
The area of the new garden=
=(40-20- 40*20/100)%
=(20-80)%
=12%

Q.4 If you have a spinning wheel with 3 green sectors, 1 blue sector and 1 red sector, what is the probability of getting a green sector? What is the probability of getting a non blue sector?

A) Green = 3/5 ; Non-blue = 4/5

B) Green = 2/5 ; Non-blue = 3/5

C) Green = 4/5 ; Non-blue = 3/5

D) Green = 3/5 ; Non-blue = 2/5

Ans. A

Total number of events = 5

Q.5 A bag has 4 red balls and 2 yellow balls. (The balls are identical in all respects other than colour). A ball is drawn from the bag without looking into the bag. What is probability of getting a red ball?

A) 2/3

B) 2/4

C) 2/5

D) 2/6

Ans. A

There are in all (4 + 2 =) 6 outcomes of the event. Getting a red ball
consists of 4 outcomes.

Therefore, the probability of getting a red ball is
4/6 = 2/3

Q.6 There are 2401 students in a school. P.T. teacher wants them to stand in rows and columns such that the number of rows is equal to the number of columns. Find
the number of rows.

A) 45

B) 47

C) 49

D) 51

Ans. C

Let the number of rows be x
So, the number of columns = x
Therefore, number of students = x × x = x2
Thus, x2 = 2401 gives x = Sq. root of 2401 = 49
The number of rows = 49

Q.7 The sum of a two-digit number and the number obtained by reversing the digits is 66. If the digits of the number differ by 2, find the number. How many such numbers are there?

A) 40 & 24

B) 42 & 24

C) 42 & 20

D) None of the above

Ans. B

Let the ten’s and the unit’s digits in the first number be x and y, respectively.
So, the first number may be written as 10 x + y in the expanded form (for example,56 = 10(5) + 6).
When the digits are reversed, x becomes the unit’s digit and y becomes the ten’s
digit. This number, in the expanded notation is 10y + x (for example, when 56 is
reversed, we get 65 = 10(6) + 5).
According to the given condition.
(10x + y) + (10y + x) = 66
i.e., 11(x + y) = 66
i.e., x + y = 6 (1)
We are also given that the digits differ by 2, therefore,
either x – y = 2 (2)
or y – x = 2 (3)
If x – y = 2, then solving (1) and (2) by elimination, we get x = 4 and y = 2.
In this case, we get the number 42.
If y – x = 2, then solving (1) and (3) by elimination, we get x = 2 and y = 4.
In this case, we get the number 24.
Thus, there are two such numbers 42 and 24.

Q.8 Satpal walks 2/3 km from a place P, towards east and then from there 1 5/7 km towards west. Where will he be now from P?

A) Distance of 1 1/21 km towards west of P

B) Distance of 1 7/21 km towards west of P

C) Distance of 1 1/21 km towards east of P

D) Distance of 1 7/21 km towards east of P

Ans. A

2/3 + (-1 5/7) = 2/3 + (-12)/7
= 2 * 7 / 3 * 7 + (-12) * 3 / 7 * 3
14-36 / 21 = 1 1/21

Since it is negative, it means Satpal is at a distance 1 1/21km towards west of P.

Q.9 Saili plants 4 saplings, in a row, in her garden. The distance between two adjacent saplings is ¾ m. Find the distance between the first and the last sapling

A) 3 m

B) 4 m

C) 5 m

D) 6 m

Ans. A

With 4 saplings there are 3 gaps: between 1 and 2, 2 and 3, and 3 & 4
3(3/4 m) = 9/4 m = 2.25 m

Q.10 In a class of 40 students 1/5 of the total number of students like to study English, 2/5 of the total number like to study mathematics and the remaining students like to study Science.

(i) How many students like to study English?

A) 6

B) 7

C) 8

D) 9

Ans. C

Total number of students in the class = 40.
(i) Of these 1/5 of the total number of students like to study English
Thus, the number of students who like to study English =
1/5 of 40 = 8.

(ii) How many students like to study Mathematics?

A) 14

B) 15

C) 16

D) 17

Ans. C

Total students = 40
Students who like English = 1/5 * 40 = 8
Students who like to study maths = 2/5 * 40 = 16

(iii) What fraction of the total number of students like to study Science?

A) 1/5

B) 2/5

C) 3/5

D) 4/5

Ans. B

Students who like to study science = 16/40 = 2/5

Q.11 Lipika reads a book for 1 ¾ hours every day. She reads the entire book in 6 days. How many hours in all were required by her to read the book?

A) 16

B) 17

C) 18

D) 19

Ans. D

13/4 * 6/1
13/2 * 3/1 = 39/2
Or 19 