Q.1 Assume that-
1. the hour & minute hands of a clock move without jerking.
2. the clock shows a time between 8 O’ clock & 9 O’clock.
3. the two hands of the clock are one above the other.
After how many minutes (nearest integer) will the two hands be again lying one above the other?
A) 60
B) 62
C) 65
D) 67
Ans. C
Explanation:
Reqd. time=60*60/55
=65 5/11
= 65
Q.2 A watch showed a time of fourteen min past nine (9 hrs & 14 min.) The position of hour hand of the watch are exactly interchanged . The new time shown by the watch is closest to which of the following ?
A) Fifteen minutes to three
B) Fourteen minutes to three
C) Thirteen minutes to three
D) Twelve minutes to three
Ans. B
Minute pointer when move sixty minutes the hour pointer moves five minutes. When minute pointer moves 14 minutes the hour pointer will move = 14/60 * 5 = 14/12
Hence the minute pointer will be act
45+14/12 = 277/6
Q. 3 Find the time between 8’o clock & 9’o clock when the two hands of a clock are 4min. apart ?
A) 39 3/11 & 48 min.
B) 40 3/11 & 47 min.
C) 41 3/11 & 46 min.
D) 42 3/11 & 45 min.
Ans. A
Shortcut:
Use this formula
(5x±4) * 12/11
(5 * 8±4) * 12/11 (In place of x you have to put 8 as given in question)
40 ± 4 *12/11
12/11 (36 & 44)
432/11 & 48
=39 3/11 & 48 min.
Q.4 Find the angle between the two hands of a clock at 15min. past 4’o clock ?
A) 37.50
B) 38.50
C) 39.50
D) 40.50
Ans. A
Shortcut:
Use this formula to find the angle:
Angle= 30(N-M/5)+M/2
Then, now put values
30 (4-15/2)+15/2
=30+7.5
=37.50
Q.5 Find the time between 8’0 clock & 9’0 clock when the two hands of a clock in the same straight line ?
A) 10 10/11 & 43 7/11
B) 11 11/11 & 44 7/11
C) 12 12/11 & 45 7/11
D) None of the above
Ans. A
Use the shortcut & apply the formula, i.e
(5x-30)*12/11 & 5x*12/11
(5*8-30)*12/11 & 5*8*12/11
120/11 & 480/11
10 10/11 & 43 7/11
